qu.1.topic=<strong>Ch 13</strong>, <font size="-1"><b>Sec 1</b></font> - Periodic Motion@

qu.1.1.mode=Randomized Formula@
qu.1.1.editing=useHTML@
qu.1.1.name=Merry-go-around@
qu.1.1.question=A child on a merry-go-around completes a full rotation in $t s.  What is the $frequency of rotation?  Give the answer in <i>$units</i>.@
qu.1.1.answer=$ans $units (1 ? 0.05)@
qu.1.1.random=
		$integer\=rint(2);
		$t\=rand(5,15,3);
		$frequency\=switch($integer,"frequency","angular frequency");
		$units\=switch($integer,"Hz","rad/s");
		$ans1\=switch($integer,1/$t,2*3.14/$t);
		$ans\=sig(3,$ans1)@

qu.1.2.mode=Randomized Formula@
qu.1.2.editing=useHTML@
qu.1.2.name=rpm->Hz@
qu.1.2.question=Convert $rpm rev/min (revolutions per minute) to Hz.@
qu.1.2.answer=$ans Hz (1 ? 0.05)@
qu.1.2.random=
		$rpm\=rand(20,200,3);
		$ans\=sig(3,$rpm/60)@

qu.1.3.mode=Randomized Formula@
qu.1.3.editing=useHTML@
qu.1.3.name=rpm-rad/s@
qu.1.3.question=The angular frequency of a point on a rotating wheel is $rpm rev/min (revolutions per minute).  What is this angular frequency in <i>rad</i>/<i>s</i>?@
qu.1.3.answer=$ans rad/s (1 ? 0.05)@
qu.1.3.random=
		$rpm\=rand(20,200,3);
		$ans\=sig(3,2*3.14/60*$rpm)@

qu.1.4.mode=Randomized Formula@
qu.1.4.editing=useHTML@
qu.1.4.name=<font face=symbol>w</font>-T@
qu.1.4.question=The angular frequency of a point on a rotating wheel is $w rad/s.  What is the period of rotation of that point?@
qu.1.4.answer=$ans s (1 ? 0.05)@
qu.1.4.random=
		$w\=rand(10,50,3);
		$f\=$w/(2*3.14);
		$ans\=sig(3,1/$f)@

qu.2.topic=<strong>Ch 13</strong>, <font size="-1"><b>Sec 2</b></font> - Simple Harmonic Motion@

qu.2.1.mode=Randomized Formula@
qu.2.1.editing=useHTML@
qu.2.1.name=Equation of Motion@
qu.2.1.question=The position of an oscillating object is described by the following equation: <i>x</i> = <font>$A</font>cos($w<i>t</i>).  What is the $question of the oscillation?@
qu.2.1.answer=$ans $units (1 ? 0.05)@
qu.2.1.random=
		
		$integer\=rint(4);
		$A\=rand(3,10,3);
		$w\=rand(5,20,3);
		$question\=switch($integer,"amplitude","frequency","angular frequency (in <i>rad</i>/<i>s</i>)","period");
		$units\=switch($integer,"m","Hz","rad/s","s");
		$ans1\=switch($integer,$A,$w/(2*3.14),$w,(2*3.14)/$w);
		$ans\=sig(3,$ans1)@

qu.3.topic=<strong>Ch 13</strong>, <font size="-1"><b>Sec 3</b></font> - Connections Between Uniform Circular Motion and Simple Harmonic Motion@

qu.3.1.mode=Randomized Formula@
qu.3.1.editing=useHTML@
qu.3.1.name=<i>a</i>(<i>t</i>)@
qu.3.1.question=The acceleration of a body in simple harmonic motion is represented by the formula <i>a</i> = &minus; <font>$k</font>cos(<font face=symbol>w</font><i>t</i>), where <i>a</i> is the acceleration, and <font face=symbol>w</font> is the angular frequency.  Knowing that the amplitude of oscillation is $A m, find the $period.@
qu.3.1.answer=$ans $units (1 ? 0.05)@
qu.3.1.random=
		$integer\=rint(4);
		$period\=switch($integer,"period","angular frequency (in <i>rad/s</i>)","frequency","maximum speed");
		$units\=switch($integer,"s","rad/s","Hz","m/s");
		$A\=rand(0.3,5,3);
		$k\=rand(5,25,3);
		$ans1\=switch($integer,2*3.14*($A)^(0.5)/($k)^(0.5),($k/$A)^(0.5),(1/(2*3.14))*($k/$A)^(0.5),$A*($k/$A)^(0.5));
		$ans=sig(3,$ans1)@

qu.4.topic=<strong>Ch 13</strong>, <font size="-1"><b>Sec 4</b></font> - The Period of a Mass on a Spring@

qu.4.1.mode=Randomized Formula@
qu.4.1.editing=useHTML@
qu.4.1.name=Mass on Spring@
qu.4.1.question=A $m-kg mass is attached to a vertical spring.  Knowing that the force constant of the spring equals $k N/m and that the maximum acceleration of the mass is $a m/s<sup>2</sup>, find the amplitude of oscillation.@
qu.4.1.answer=$ans m (1 ? 0.05)@
qu.4.1.random=
		$m\=rand(1.2,5,3);
		$k\=rand(300,700,3);
		$a\=rand(10,25,3);
		$ans\=sig(3,$a*$m/$k)@

qu.5.topic=<strong>Ch 13</strong>, <font size="-1"><b>Sec 5</b></font> - Energy Conservation in Oscillatory Motion@

qu.5.1.mode=Randomized Formula@
qu.5.1.editing=useHTML@
qu.5.1.name=<i>U</i> of Mass on Spring@
qu.5.1.question=A spring positioned vertically with a $m-kg mass attached to its end is stretched by <font face=symbol>D</font><i>x</i> = $dx cm past the equilibrium position.  At time t = 0 s the mass is released.  Find the potential energy of the mass $t s later if the force constant of the spring is $k N/m.@
qu.5.1.answer=$ans J (1 ? 0.05)@
qu.5.1.random=
		$m\=rand(2,8,3);
		$dx\=rand(3,15,3);
		$t\=rand(0.8,6,3);
		$k\=rand(300,700,3);
		$ans\=sig(3,0.5*$k*($dx/100)^2*(cos($t*($k/$m)^0.5))^2)@

qu.6.topic=<strong>Ch 13</strong>, <font size="-1"><b>Sec 6</b></font> - The Pendulum@

qu.6.1.mode=Randomized Formula@
qu.6.1.editing=useHTML@
qu.6.1.name=Physical Pendulum 1@
qu.6.1.question=An odd-shaped $m-kg physical pendulum is oscillating with a period of $period s.  What is the distance between the pivot point and the center of mass of the pendulum if its moment of inertia is $I kg&middot;m<sup>2</sup>?  Assume the acceleration due to gravity to be 9.81 m/s<sup>2</sup>.@
qu.6.1.answer=$ans m (1 ? 0.05)@
qu.6.1.random=
		$period\=rand(2,6,3);
		$I\=rand(5,25,3);
		$m\=rand(2,7,3);
		$ans\=sig(3,(2*3.14/$period)^2*($I/(9.81*$m)))@