qu.env.lastSaved=
Aug 10, 2005 9:27:45 PM
@
qu.env.validTest=
false
@
qu.1.topic=8_1 MC Supplementary/Complementary@
qu.1.1.mode=Non Permuting Multiple Choice@
qu.1.1.name=Supplementary@
qu.1.1.comment=Determine if 
1 and 2 are supplementary, complementary, or neither given:
1 = ${$a}° and 2 = ${$s}°
1 + 2 = ${$a}° + ${$s}° = ${$a+$s}°
Since the angles add to 180°, they are supplementary angles.
@
qu.1.1.editing=useHTML@
qu.1.1.algorithm=$a=range(50,70,1);
$s=180-$a;
$c=90-$a;
$n=180-$a-2;@
qu.1.1.question=Determine if 1 and 2 are supplementary, complementary, or neither given:
1 = ${$a}° and 2 = ${$s}°
@
qu.1.1.answer=2@
qu.1.1.choice.1=Complementary@
qu.1.1.choice.2=Supplementary@
qu.1.1.choice.3=Neither@
qu.1.2.mode=Non Permuting Multiple Choice@
qu.1.2.name=Complementary@
qu.1.2.comment=Determine if 1 and 2 are supplementary, complementary, or neither given:
1 = ${$a}° and 2 = ${$c}°
1 + 2 = ${$a}° + ${$c}° = ${$a+$c}°
Since the angles add to 90°, they are complementary angles.
@
qu.1.2.editing=useHTML@
qu.1.2.algorithm=$a=range(50,70,1);
$s=180-$a;
$c=90-$a;
$n=180-$a-2;@
qu.1.2.question=Determine if 1 and 2 are supplementary, complementary, or neither given:
1 = ${$a}° and 2 = ${$c}°
@
qu.1.2.answer=1@
qu.1.2.choice.1=Complementary@
qu.1.2.choice.2=Supplementary@
qu.1.2.choice.3=Neither@
qu.1.3.mode=Non Permuting Multiple Choice@
qu.1.3.name=Neither@
qu.1.3.comment=Determine if 1 and 2 are supplementary, complementary, or neither given:
1 = ${$a}° and 2 = ${$n}°
1 + 2 = ${$a}° + ${$n}° = ${$a+$n}°
Since the angles add to 90° or 180°, they are neither complementary nor supplementary angles.
@
qu.1.3.editing=useHTML@
qu.1.3.algorithm=$a=range(50,70,1);
$s=180-$a;
$c=90-$a;
$n=180-$a-2;@
qu.1.3.question=Determine if 1 and 2 are supplementary, complementary, or neither given:
1 = ${$a}° and 2 = ${$n}°
@
qu.1.3.answer=3@
qu.1.3.choice.1=Complementary@
qu.1.3.choice.2=Supplementary@
qu.1.3.choice.3=Neither@
qu.2.topic=8_1 Find Supplement/Complement@
qu.2.1.question=1 and 2 are supplementary. Determine the 2 if 1 = ${$a}°.
Do not enter a degree symbol in the answer box.@
qu.2.1.answer.num=$s@
qu.2.1.answer.units=@
qu.2.1.showUnits=false@
qu.2.1.grading=exact_value@
qu.2.1.negStyle=both@
qu.2.1.numStyle=thousands scientific dollars @
qu.2.1.mode=Numeric@
qu.2.1.name=Supplement@
qu.2.1.comment=1 and 2 are supplementary. Determine the 2 if 1 = ${$a}°.
Supplementary angles add to 180°.
${$a}° + 2 =180°
2 = ${$s}°
@
qu.2.1.editing=useHTML@
qu.2.1.algorithm=$a=range(50,70,1);
$s=180-$a;
$c=90-$a;@
qu.2.2.question=1 and 2 are complementary. Determine the 2 if 1 = ${$a}°.
Do not enter a degree symbol in the answer box.@
qu.2.2.answer.num=$c@
qu.2.2.answer.units=@
qu.2.2.showUnits=false@
qu.2.2.grading=exact_value@
qu.2.2.negStyle=both@
qu.2.2.numStyle=thousands scientific dollars @
qu.2.2.mode=Numeric@
qu.2.2.name=Complement@
qu.2.2.comment=1 and 2 are complementary. Determine the 2 if 1 = ${$a}°.
Complementary angles add to 90°.
${$a}° + 2 = 90°
2 = ${$c}°
@
qu.2.2.editing=useHTML@
qu.2.2.algorithm=$a=range(50,70,1);
$s=180-$a;
$c=90-$a;@
qu.3.topic=8_1 Find Angle Measures A@
qu.3.1.mode=Inline@
qu.3.1.name=Angles@
qu.3.1.comment=
Given 1 = $a1 °, find:
1 and 2 are supplementary.
1 + 2 = 180°
${$a1}° + 2 = 180°
2 = ${$a2}°
1 and 3 are vertical angles.
3 = 1 = ${$a1}°
2 and 4 are vertical angles.
4 = 2 = ${$a2}°
@
qu.3.1.editing=useHTML@
qu.3.1.algorithm=$a1=range(30,50,1);
$a2=180-$a1;
$a4=$a2;
$a3=$a1;@
qu.3.1.weighting=1,1,1@
qu.3.1.numbering=alpha@
qu.3.1.part.1.name=$a2@
qu.3.1.part.1.answer.units=@
qu.3.1.part.1.numStyle=thousands scientific arithmetic@
qu.3.1.part.1.editing=useHTML@
qu.3.1.part.1.showUnits=false@
qu.3.1.part.1.question=(Unset)@
qu.3.1.part.1.mode=Numeric@
qu.3.1.part.1.grading=exact_value@
qu.3.1.part.1.negStyle=minus@
qu.3.1.part.1.answer.num=$a2@
qu.3.1.part.2.name=$a3@
qu.3.1.part.2.answer.units=@
qu.3.1.part.2.numStyle=thousands scientific arithmetic@
qu.3.1.part.2.editing=useHTML@
qu.3.1.part.2.showUnits=false@
qu.3.1.part.2.question=(Unset)@
qu.3.1.part.2.mode=Numeric@
qu.3.1.part.2.grading=exact_value@
qu.3.1.part.2.negStyle=minus@
qu.3.1.part.2.answer.num=$a3@
qu.3.1.part.3.name=$a4@
qu.3.1.part.3.answer.units=@
qu.3.1.part.3.numStyle=thousands scientific arithmetic@
qu.3.1.part.3.editing=useHTML@
qu.3.1.part.3.showUnits=false@
qu.3.1.part.3.question=(Unset)@
qu.3.1.part.3.mode=Numeric@
qu.3.1.part.3.grading=exact_value@
qu.3.1.part.3.negStyle=minus@
qu.3.1.part.3.answer.num=$a4@
qu.3.1.question=
Given 1
= $a1 °, find:
2 = <1>
3
= <2>
4
= <3>
Do not enter the degree symbol into the answer box.
@
qu.3.2.mode=Inline@
qu.3.2.name=Angles2@
qu.3.2.comment=
Given 1 = a1 °, find:
1 and 2 are supplementary.
1 + 2 = 180°
${$a1}° + 2 = 180°
2 = ${$a2}°
1 and 3 are vertical angles.
3 = 1 = ${$a1}°
2 and 4 are vertical angles.
4 = 2 = ${$a2}°
@
qu.3.2.editing=useHTML@
qu.3.2.algorithm=$a1=range(120,150,1);
$a2=180-$a1;
$a4=$a2;
$a3=$a1;@
qu.3.2.weighting=1,1,1@
qu.3.2.numbering=alpha@
qu.3.2.part.1.name=$a2@
qu.3.2.part.1.answer.units=@
qu.3.2.part.1.numStyle=thousands scientific arithmetic@
qu.3.2.part.1.editing=useHTML@
qu.3.2.part.1.showUnits=false@
qu.3.2.part.1.question=(Unset)@
qu.3.2.part.1.mode=Numeric@
qu.3.2.part.1.grading=exact_value@
qu.3.2.part.1.negStyle=minus@
qu.3.2.part.1.answer.num=$a2@
qu.3.2.part.2.name=$a3@
qu.3.2.part.2.answer.units=@
qu.3.2.part.2.numStyle=thousands scientific arithmetic@
qu.3.2.part.2.editing=useHTML@
qu.3.2.part.2.showUnits=false@
qu.3.2.part.2.question=(Unset)@
qu.3.2.part.2.mode=Numeric@
qu.3.2.part.2.grading=exact_value@
qu.3.2.part.2.negStyle=minus@
qu.3.2.part.2.answer.num=$a3@
qu.3.2.part.3.name=$a4@
qu.3.2.part.3.answer.units=@
qu.3.2.part.3.numStyle=thousands scientific arithmetic@
qu.3.2.part.3.editing=useHTML@
qu.3.2.part.3.showUnits=false@
qu.3.2.part.3.question=(Unset)@
qu.3.2.part.3.mode=Numeric@
qu.3.2.part.3.grading=exact_value@
qu.3.2.part.3.negStyle=minus@
qu.3.2.part.3.answer.num=$a4@
qu.3.2.question=
Given 1
= $a1 °, find:
2 = <1>
3
= <2>
4
= <3>
Do not enter the degree symbol into the answer box.
@
qu.4.topic=8_1 Find Angle Measures B@
qu.4.1.mode=Inline@
qu.4.1.name=Comp Given 3@
qu.4.1.comment=
Given 3 = $a3°,
Since 2 is a right angle, the lines forming this angle are perpendicular and all angles between these two lines are 90°.
The 1 = 90°.
3 and 4 are complementary angles adding to 90°.
3 + 4 = 180°
${$a3}° + 4 = 180°
4 = ${$a4}°
@
qu.4.1.editing=useHTML@
qu.4.1.algorithm=$a3=range(15,45,1);
$a4=90-$a3;
$a1=90;
$a2=90;
$a5=90;@
qu.4.1.weighting=1,1@
qu.4.1.numbering=alpha@
qu.4.1.part.1.name=$a1@
qu.4.1.part.1.answer.units=@
qu.4.1.part.1.numStyle=thousands scientific arithmetic@
qu.4.1.part.1.editing=useHTML@
qu.4.1.part.1.showUnits=false@
qu.4.1.part.1.question=(Unset)@
qu.4.1.part.1.mode=Numeric@
qu.4.1.part.1.grading=exact_value@
qu.4.1.part.1.negStyle=minus@
qu.4.1.part.1.answer.num=$a1@
qu.4.1.part.2.name=$a4@
qu.4.1.part.2.answer.units=@
qu.4.1.part.2.numStyle=thousands scientific arithmetic@
qu.4.1.part.2.editing=useHTML@
qu.4.1.part.2.showUnits=false@
qu.4.1.part.2.question=(Unset)@
qu.4.1.part.2.mode=Numeric@
qu.4.1.part.2.grading=exact_value@
qu.4.1.part.2.negStyle=minus@
qu.4.1.part.2.answer.num=$a4@
qu.4.1.question=
Given 3
= $a3°, find:
1 = <1>
4
= <2>
Do not enter the degree symbol into the answer box.
@
qu.4.2.mode=Inline@
qu.4.2.name=Comp Given 4@
qu.4.2.comment=
Given 4 = $a4°,
Since 2 is a right angle, the lines forming this angle are perpendicular and all angles between these two lines are 90°.
The 5 = 90°.
3 and 4 are complementary angles adding to 90°.
3 + 4 = 90°
3 + ${$a4}° = 90°
3 = ${$a3}°
@
qu.4.2.editing=useHTML@
qu.4.2.algorithm=$a3=range(15,45,1);
$a4=90-$a3;
$a1=90;
$a2=90;
$a5=90;@
qu.4.2.weighting=1,1@
qu.4.2.numbering=alpha@
qu.4.2.part.1.name=$a3@
qu.4.2.part.1.answer.units=@
qu.4.2.part.1.numStyle=thousands scientific arithmetic@
qu.4.2.part.1.editing=useHTML@
qu.4.2.part.1.showUnits=false@
qu.4.2.part.1.question=(Unset)@
qu.4.2.part.1.mode=Numeric@
qu.4.2.part.1.grading=exact_value@
qu.4.2.part.1.negStyle=minus@
qu.4.2.part.1.answer.num=$a3@
qu.4.2.part.2.name=$a5@
qu.4.2.part.2.answer.units=@
qu.4.2.part.2.numStyle=thousands scientific arithmetic@
qu.4.2.part.2.editing=useHTML@
qu.4.2.part.2.showUnits=false@
qu.4.2.part.2.question=(Unset)@
qu.4.2.part.2.mode=Numeric@
qu.4.2.part.2.grading=exact_value@
qu.4.2.part.2.negStyle=minus@
qu.4.2.part.2.answer.num=$a5@
qu.4.2.question=
Given 4
= $a4°, find:
3 = <1>
5
= <2>
Do not enter the degree symbol into the answer box.
@
qu.5.topic=8_1 Find Angle Measures C@
qu.5.1.mode=Inline@
qu.5.1.name=Given 1@
qu.5.1.comment=
Given 1 = $a1°,
1 and 3 are corresponding angles with equal measures.
3 = 1 = ${$a1}°
3 and 4 are supplementary angles adding to 180°.
3 + 4 = 180°
${$a3}° + 4 = 180°
4 = ${$a4}°
3 and 5 are vertical angles with equal measures.
5 = 3 = ${$a5}°
4 and 6 are vertical angles with equal measures.
6= 4 = ${$a6}°
@
qu.5.1.editing=useHTML@
qu.5.1.algorithm=$a1=range(30,60,1);
$a2=180-$a1;
$a3=$a1;
$a4=$a2;
$a5=$a1;
$a6=$a2;
$a7=$a1;
$a8=$a2;@
qu.5.1.weighting=1,1,1,1@
qu.5.1.numbering=alpha@
qu.5.1.part.1.name=$a3@
qu.5.1.part.1.answer.units=@
qu.5.1.part.1.numStyle=thousands scientific arithmetic@
qu.5.1.part.1.editing=useHTML@
qu.5.1.part.1.showUnits=false@
qu.5.1.part.1.question=(Unset)@
qu.5.1.part.1.mode=Numeric@
qu.5.1.part.1.grading=exact_value@
qu.5.1.part.1.negStyle=minus@
qu.5.1.part.1.answer.num=$a3@
qu.5.1.part.2.name=$a4@
qu.5.1.part.2.answer.units=@
qu.5.1.part.2.numStyle=thousands scientific arithmetic@
qu.5.1.part.2.editing=useHTML@
qu.5.1.part.2.showUnits=false@
qu.5.1.part.2.question=(Unset)@
qu.5.1.part.2.mode=Numeric@
qu.5.1.part.2.grading=exact_value@
qu.5.1.part.2.negStyle=minus@
qu.5.1.part.2.answer.num=$a4@
qu.5.1.part.3.name=$a5@
qu.5.1.part.3.answer.units=@
qu.5.1.part.3.numStyle=thousands scientific arithmetic@
qu.5.1.part.3.editing=useHTML@
qu.5.1.part.3.showUnits=false@
qu.5.1.part.3.question=(Unset)@
qu.5.1.part.3.mode=Numeric@
qu.5.1.part.3.grading=exact_value@
qu.5.1.part.3.negStyle=minus@
qu.5.1.part.3.answer.num=$a5@
qu.5.1.part.4.name=$a6@
qu.5.1.part.4.answer.units=@
qu.5.1.part.4.numStyle=thousands scientific arithmetic@
qu.5.1.part.4.editing=useHTML@
qu.5.1.part.4.showUnits=false@
qu.5.1.part.4.question=(Unset)@
qu.5.1.part.4.mode=Numeric@
qu.5.1.part.4.grading=exact_value@
qu.5.1.part.4.negStyle=minus@
qu.5.1.part.4.answer.num=$a6@
qu.5.1.question=
Given 1
= $a1 °, find:
3 = <1>
4
= <2>
5
= <3>
6
= <4>
Do not enter the degree symbol into the answer box.
@
qu.5.2.mode=Inline@
qu.5.2.name=Given 3@
qu.5.2.comment=
Given 3 = $a3°,
1 and 3 are corresponding angles with equal measures.
1 = 3 = ${$a1}°
1 and 2 are supplementary angles adding to 180°.
1 + 2 = 180°
${$a1}° + 2 = 180°
2 = ${$a2}°
3 and 5 are vertical angles with equal measures.
5 = 3 = ${$a5}°
2 and 6 are alternate interior angles.
6 = 2 = ${$a6}°
@
qu.5.2.editing=useHTML@
qu.5.2.algorithm=$a3=range(30,60,1);
$a4=180-$a3;
$a1=$a3;
$a2=$a4;
$a5=$a1;
$a6=$a2;
$a7=$a1;
$a8=$a2;@
qu.5.2.weighting=1,1,1,1@
qu.5.2.numbering=alpha@
qu.5.2.part.1.name=$a1@
qu.5.2.part.1.answer.units=@
qu.5.2.part.1.numStyle=thousands scientific arithmetic@
qu.5.2.part.1.editing=useHTML@
qu.5.2.part.1.showUnits=false@
qu.5.2.part.1.question=(Unset)@
qu.5.2.part.1.mode=Numeric@
qu.5.2.part.1.grading=exact_value@
qu.5.2.part.1.negStyle=minus@
qu.5.2.part.1.answer.num=$a1@
qu.5.2.part.2.name=$a2@
qu.5.2.part.2.answer.units=@
qu.5.2.part.2.numStyle=thousands scientific arithmetic@
qu.5.2.part.2.editing=useHTML@
qu.5.2.part.2.showUnits=false@
qu.5.2.part.2.question=(Unset)@
qu.5.2.part.2.mode=Numeric@
qu.5.2.part.2.grading=exact_value@
qu.5.2.part.2.negStyle=minus@
qu.5.2.part.2.answer.num=$a2@
qu.5.2.part.3.name=$a5@
qu.5.2.part.3.answer.units=@
qu.5.2.part.3.numStyle=thousands scientific arithmetic@
qu.5.2.part.3.editing=useHTML@
qu.5.2.part.3.showUnits=false@
qu.5.2.part.3.question=(Unset)@
qu.5.2.part.3.mode=Numeric@
qu.5.2.part.3.grading=exact_value@
qu.5.2.part.3.negStyle=minus@
qu.5.2.part.3.answer.num=$a5@
qu.5.2.part.4.name=$a6@
qu.5.2.part.4.answer.units=@
qu.5.2.part.4.numStyle=thousands scientific arithmetic@
qu.5.2.part.4.editing=useHTML@
qu.5.2.part.4.showUnits=false@
qu.5.2.part.4.question=(Unset)@
qu.5.2.part.4.mode=Numeric@
qu.5.2.part.4.grading=exact_value@
qu.5.2.part.4.negStyle=minus@
qu.5.2.part.4.answer.num=$a6@
qu.5.2.question=
Given 3
= $a3°, find:
1 = <1>
2
= <2>
5
= <3>
6
= <4>
Do not enter the degree symbol into the answer box.
@
qu.5.3.mode=Inline@
qu.5.3.name=Given 6@
qu.5.3.comment=
Given 6 = ${$a6}°,
6 and 4 are vertical angles with equal measures.
6 = 4 = ${$a6}°
6 and 3 are supplementary angles adding to 180°.
6 + 3 = 180°
${$a6}° + 3 = 180°
3 = ${$a3}°
6 and 2 are alternate interior angles with equal measures.
2 = 6 = ${$a6}°
3 and 1 are corresponding angles with equal measures.
1 = 3 = ${$a1}°
@
qu.5.3.editing=useHTML@
qu.5.3.algorithm=$a6=range(110,160,1);
$a3=180-$a6;
$a1=$a3;
$a2=$a6;
$a4=$a6;
$a5=$a3;
$a7=$a1;
$a8=$a2;@
qu.5.3.weighting=1,1,1,1@
qu.5.3.numbering=alpha@
qu.5.3.part.1.name=$a1@
qu.5.3.part.1.answer.units=@
qu.5.3.part.1.numStyle=thousands scientific arithmetic@
qu.5.3.part.1.editing=useHTML@
qu.5.3.part.1.showUnits=false@
qu.5.3.part.1.question=(Unset)@
qu.5.3.part.1.mode=Numeric@
qu.5.3.part.1.grading=exact_value@
qu.5.3.part.1.negStyle=minus@
qu.5.3.part.1.answer.num=$a1@
qu.5.3.part.2.name=$a2@
qu.5.3.part.2.answer.units=@
qu.5.3.part.2.numStyle=thousands scientific arithmetic@
qu.5.3.part.2.editing=useHTML@
qu.5.3.part.2.showUnits=false@
qu.5.3.part.2.question=(Unset)@
qu.5.3.part.2.mode=Numeric@
qu.5.3.part.2.grading=exact_value@
qu.5.3.part.2.negStyle=minus@
qu.5.3.part.2.answer.num=$a2@
qu.5.3.part.3.name=$a3@
qu.5.3.part.3.answer.units=@
qu.5.3.part.3.numStyle=thousands scientific arithmetic@
qu.5.3.part.3.editing=useHTML@
qu.5.3.part.3.showUnits=false@
qu.5.3.part.3.question=(Unset)@
qu.5.3.part.3.mode=Numeric@
qu.5.3.part.3.grading=exact_value@
qu.5.3.part.3.negStyle=minus@
qu.5.3.part.3.answer.num=$a3@
qu.5.3.part.4.name=$a4@
qu.5.3.part.4.answer.units=@
qu.5.3.part.4.numStyle=thousands scientific arithmetic@
qu.5.3.part.4.editing=useHTML@
qu.5.3.part.4.showUnits=false@
qu.5.3.part.4.question=(Unset)@
qu.5.3.part.4.mode=Numeric@
qu.5.3.part.4.grading=exact_value@
qu.5.3.part.4.negStyle=minus@
qu.5.3.part.4.answer.num=$a4@
qu.5.3.question=
Given 6
= $a6°, find:
1 = <1>
2
= <2>
3
= <3>
4
= <4>
Do not enter the degree symbol into the answer box.
@
qu.6.topic=8_2 Classify Triangles@
qu.6.1.mode=Matching@
qu.6.1.name=Angles@
qu.6.1.comment=Classify the triangles. Match each triangle to its classification.
right - contains one right angle
obtuse - contains one angle greater than 90°
acute - all angles are less than 90°
@
qu.6.1.editing=useHTML@
qu.6.1.format.columns=1@
qu.6.1.question=Classify the triangles. Match each triangle to its classification.@
qu.6.1.term.1=@
qu.6.1.term.1.def.1=right@
qu.6.1.term.2=@
qu.6.1.term.2.def.1=obtuse@
qu.6.1.term.3=@
qu.6.1.term.3.def.1=acute@
qu.6.2.mode=Matching@
qu.6.2.name=Sides@
qu.6.2.comment=
equilateral - all three sides are the same length
scalene - no sides have equal length
isosceles - 2 sides have equal length
@
qu.6.2.editing=useHTML@
qu.6.2.format.columns=1@
qu.6.2.question=Classify the triangles. Match each triangle to its classification.
@
qu.6.2.term.1=@
qu.6.2.term.1.def.1=equilateral@
qu.6.2.term.2=@
qu.6.2.term.2.def.1=scalene@
qu.6.2.term.3=@
qu.6.2.term.3.def.1=isosceles@
qu.7.topic=8_2 Solve for an Angle A@
qu.7.1.question=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.7.1.answer.num=$ans@
qu.7.1.answer.units=@
qu.7.1.showUnits=false@
qu.7.1.grading=exact_value@
qu.7.1.negStyle=minus@
qu.7.1.numStyle=thousands scientific dollars arithmetic@
qu.7.1.mode=Numeric@
qu.7.1.name=Right 1@
qu.7.1.comment=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + ${$a1}° + 90° = 180°
$x° + ${$a1}° = 90° (The acute angles of a right triangle sum to 90°.)
$x° = ${$ans}°
@
qu.7.1.editing=useHTML@
qu.7.1.algorithm=$a1=range(10,40,1);
$a2=90;
$ans=180-$a1-$a2;
$x=switch(rint(3),"x","y","z");@
qu.7.2.question=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.7.2.answer.num=$ans@
qu.7.2.answer.units=@
qu.7.2.showUnits=false@
qu.7.2.grading=exact_value@
qu.7.2.negStyle=minus@
qu.7.2.numStyle=thousands scientific dollars arithmetic@
qu.7.2.mode=Numeric@
qu.7.2.name=Isosceles@
qu.7.2.comment=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + ${$a1}° + ${$a2}° = 180°
$x° + ${$a1+$a2}° = 180°
$x° = ${$ans}°
@
qu.7.2.editing=useHTML@
qu.7.2.algorithm=$a1=range(30,60,1);
$a2=$a1;
$ans=180-$a1-$a2;
$x=switch(rint(3),"x","y","z");@
qu.7.3.question=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.7.3.answer.num=$ans@
qu.7.3.answer.units=@
qu.7.3.showUnits=false@
qu.7.3.grading=exact_value@
qu.7.3.negStyle=minus@
qu.7.3.numStyle=thousands scientific dollars arithmetic@
qu.7.3.mode=Numeric@
qu.7.3.name=Scalene@
qu.7.3.comment=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + ${$a1}° + ${$a2}° = 180°
$x° + ${$a1+$a2}° = 180°
$x° = ${$ans}°
@
qu.7.3.editing=useHTML@
qu.7.3.algorithm=$a1=range(30,60,1);
$a2=range(90,120,1);
$ans=180-$a1-$a2;
condition:gt($ans,10);
condition:ne($an,$a1);
$x=switch(rint(3),"x","y","z");@
qu.8.topic=8_2 Solve for an Angle B@
qu.8.1.question=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.8.1.answer.num=$ans@
qu.8.1.answer.units=@
qu.8.1.showUnits=false@
qu.8.1.grading=exact_value@
qu.8.1.negStyle=minus@
qu.8.1.numStyle=thousands scientific dollars arithmetic@
qu.8.1.mode=Numeric@
qu.8.1.name=Right@
qu.8.1.comment=
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + (${$a}$x + $b)° + 90° = 180°
$x° + (${$a}$x + $b)° = 90° (The acute angles sum to 90°.)
(${$a+1}$x + $b)° = 90°
${$a+1}$x° = ${90-$b}°
$x° = $ans°
@
qu.8.1.editing=useHTML@
qu.8.1.algorithm=$ans=range(15,29,1);
$a=int(89/$ans)-1;
$b=90-($a+1)*$ans;
condition:gt($b,0);
condition:gt($a,1);
$x=switch(rint(3),"x","y","z");@
qu.8.2.question=
 |
 |
$x° |
 |
 |
(${$a}$x + $b)° |
 |
${$a1}° |
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.8.2.answer.num=$ans@
qu.8.2.answer.units=@
qu.8.2.showUnits=false@
qu.8.2.grading=exact_value@
qu.8.2.negStyle=minus@
qu.8.2.numStyle=thousands scientific dollars arithmetic@
qu.8.2.mode=Numeric@
qu.8.2.name=Scalene@
qu.8.2.comment=
|
|
$x° |
|
|
(${$a}$x + $b)° |
|
${$a1}° |
Solve for $x in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + (${$a}$x + $b)° + ${$a1}° = 180°
(${$a+1}$x + ${$a1+$b})° = 180°
${$a+1}$x° = ${180-($a1+$b)}°
$x° = ${$ans}°
@
qu.8.2.editing=useHTML@
qu.8.2.algorithm=$ans=range(15,29,1);
$a1=range(15,29,1);
condition:ne($ans,$a1);
$a=int((180-$a1-$ans)/$ans);
$b=180-($a+1)*$ans-$a1;
condition:gt($b,0);
condition:gt($a,1);
$x=switch(rint(3),"x","y","z");@
qu.9.topic=8_2 Solve for an Angle C@
qu.9.1.question=
Solve for the largest non-right angle in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.9.1.answer.num=$ans2@
qu.9.1.answer.units=@
qu.9.1.showUnits=false@
qu.9.1.grading=exact_value@
qu.9.1.negStyle=minus@
qu.9.1.numStyle=thousands scientific dollars arithmetic@
qu.9.1.mode=Numeric@
qu.9.1.name=Right@
qu.9.1.comment=
Solve for the largest non-right angle in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + (${$a}$x + $b)° + 90° = 180°
$x° + (${$a}$x + $b)° = 90° (The acute angles sum to 90°.)
(${$a+1}$x + $b)° = 90°
${$a+1}$x° = ${90-$b}°
$x° = $ans°
The other angle is (${$a}$x + $b)° = (${$a*$ans} + $b)° = ${$a*$ans+$b}°
The largest non-right angle is $ans2°
@
qu.9.1.editing=useHTML@
qu.9.1.algorithm=$ans=range(15,29,1);
$a=int(89/$ans)-1;
$b=90-($a+1)*$ans;
condition:gt($b,0);
condition:gt($a,1);
$x=switch(rint(3),"x","y","z");
$ans2=max($ans,90-$ans);@
qu.9.2.question=
|
|
$x° |
|
|
(${$a}$x + $b)° |
|
${$a1}° |
Solve for the largest angle in the triangle above.
Do not enter the ° symbol in the answer box.
@
qu.9.2.answer.num=$ans2@
qu.9.2.answer.units=@
qu.9.2.showUnits=false@
qu.9.2.grading=exact_value@
qu.9.2.negStyle=minus@
qu.9.2.numStyle=thousands scientific dollars arithmetic@
qu.9.2.mode=Numeric@
qu.9.2.name=Scalene@
qu.9.2.comment=
|
|
$x° |
|
|
(${$a}$x + $b)° |
|
${$a1}° |
Solve for the largest angle in the triangle above.
Do not enter the ° symbol in the answer box.
The interior angles of a triangle sum to 180°.
$x° + (${$a}$x + $b)° + ${$a1}° = 180°
(${$a+1}$x + ${$a1+$b})° = 180°
${$a+1}$x° = ${180-($a1+$b)}°
$x° = ${$ans}°
The other angle is (${$a}$x + $b)° = (${$a*$ans} + $b)° = ${$a*$ans+$b}°
The largest angle of the three angles is $ans2°
@
qu.9.2.editing=useHTML@
qu.9.2.algorithm=$ans=range(15,29,1);
$a1=range(15,29,1);
condition:ne($ans,$a1);
$a=int((180-$a1-$ans)/$ans);
$b=180-($a+1)*$ans-$a1;
condition:gt($b,0);
condition:gt($a,1);
$x=switch(rint(3),"x","y","z");
$ans2=$a*$ans+$b;@
qu.10.topic=8_3 Classify Quadrilaterals@
qu.10.1.mode=Matching@
qu.10.1.name=Matching@
qu.10.1.comment=Classify each quadrilateral. Match each quadrilateral with the appropriate type.
Parallelogram - Both pairs of opposite sides are parallel.
Rectangle - Four right angles
Rhombus - Four sides of equal length.
Square - Four sides of equal length and four right angles.
Trapezoid - Exactly one pair of parallel lines.
@
qu.10.1.editing=useHTML@
qu.10.1.format.columns=2@
qu.10.1.question=Classify each quadrilateral. Match each quadrilateral with the appropriate type.
@
qu.10.1.term.1=@
qu.10.1.term.1.def.1=Parallelogram@
qu.10.1.term.2=@
qu.10.1.term.2.def.1=Rectangle@
qu.10.1.term.3=@
qu.10.1.term.3.def.1=Rhombus@
qu.10.1.term.4=@
qu.10.1.term.4.def.1=Square@
qu.10.1.term.5=@
qu.10.1.term.5.def.1=Trapezoid@
qu.11.topic=8_3 Solve Quadrilateral Angle A@
qu.11.1.question=
Find the angle ${$x}°.
Do not enter the ° symbol into the answer box.
@
qu.11.1.answer.num=$ans@
qu.11.1.answer.units=@
qu.11.1.showUnits=false@
qu.11.1.grading=exact_value@
qu.11.1.negStyle=minus@
qu.11.1.numStyle=thousands scientific dollars arithmetic@
qu.11.1.mode=Numeric@
qu.11.1.name=Quad Angle@
qu.11.1.comment=
Find the angle ${$x}°.
Do not enter the ° symbol into the answer box.
The sum of the interior angles of a quadrilateral is 360°.
${$a1}° + ${$a2}° + ${$a3}° + ${$x}° = 360°
${$a1+$a2+$a3}° + ${$x}° = 360°
${$x}° = ${$ans}°
@
qu.11.1.editing=useHTML@
qu.11.1.algorithm=$a1=range(80,110,1);
$a2=range(70,90,2);
$a3=range(95,120,2);
$ans=360-$a1-$a2-$a3;
condition:gt($ans,0);
condition:lt($ans,90);
$i=rint(4);
$x=switch($i,"a","b","c","d");@
qu.11.2.question=
Find the angle ${$x}°.
Do not enter the ° symbol into the answer box.
@
qu.11.2.answer.num=$ans@
qu.11.2.answer.units=@
qu.11.2.showUnits=false@
qu.11.2.grading=exact_value@
qu.11.2.negStyle=minus@
qu.11.2.numStyle=thousands scientific dollars arithmetic@
qu.11.2.mode=Numeric@
qu.11.2.name=Quad Angle2@
qu.11.2.comment=
Find the angle ${$x}°.
Do not enter the ° symbol into the answer box.
The sum of the interior angles of a quadrilateral is 360°.
${$a1}° + ${$a2}° + ${$a3}° + ${$x}° = 360°
${$a1+$a2+$a3}° + ${$x}° = 360°
${$x}° = ${$ans}°
@
qu.11.2.editing=useHTML@
qu.11.2.algorithm=$a1=range(80,110,1);
$a2=range(70,90,2);
$ans=range(95,120,2);
$a3=360-$a1-$a2-$ans;
condition:gt($a3,0);
condition:lt($a3,90);
$i=rint(4);
$x=switch($i,"a","b","c","d");@
qu.12.topic=8_3 Solve Quadrilateral Angle B@
qu.12.1.mode=Inline@
qu.12.1.name=Solve Supp Angle@
qu.12.1.comment=
Find the measures of angles ${$x}° and ${$x2}°
Do not enter the ° symbol into the answer box.
The sum of the interior angles of a quadrilateral is 360°.
${$a1}° + ${$a2}° + ${$a3}° + ${$x}° = 360°
${$a1+$a2+$a3}° + ${$x}° = 360°
${$x}° = ${$ans}°
$x and $x2 are supplementary angles.
${$x}° + ${$x2}° = 180°
${$ans}° + ${$x2}° = 180°
${$x2}° = ${$ans2}°
@
qu.12.1.editing=useHTML@
qu.12.1.algorithm=$a1=range(85,120,1);
$a2=range(70,90,2);
$a3=range(95,120,2);
$ans=360-$a1-$a2-$a3;
$ans2=180-$ans;
$i=rint(3);
$x=switch($i,"a","b","c","d");
$x2=switch($i+1,"a","b","c","d");@
qu.12.1.weighting=1,1@
qu.12.1.numbering=alpha@
qu.12.1.part.1.name=$ans@
qu.12.1.part.1.answer.units=@
qu.12.1.part.1.numStyle=thousands scientific arithmetic@
qu.12.1.part.1.editing=useHTML@
qu.12.1.part.1.showUnits=false@
qu.12.1.part.1.question=(Unset)@
qu.12.1.part.1.mode=Numeric@
qu.12.1.part.1.grading=exact_value@
qu.12.1.part.1.negStyle=minus@
qu.12.1.part.1.answer.num=$ans@
qu.12.1.part.2.name=$ans2@
qu.12.1.part.2.answer.units=@
qu.12.1.part.2.numStyle=thousands scientific arithmetic@
qu.12.1.part.2.editing=useHTML@
qu.12.1.part.2.showUnits=false@
qu.12.1.part.2.question=(Unset)@
qu.12.1.part.2.mode=Numeric@
qu.12.1.part.2.grading=exact_value@
qu.12.1.part.2.negStyle=minus@
qu.12.1.part.2.answer.num=$ans2@
qu.12.1.question=
Find the measures of angles $x° and $x2°
Do
not enter the ° symbol into the answer box.
$x = <1>
$x2 = <2>
@
qu.12.2.mode=Inline@
qu.12.2.name=Triangle and Quad@
qu.12.2.comment=
Find the measure of angles f° and g°.
Do not enter the ° into the answer box.
Two of the three angles in the triangle are known. Solve for
the third angle.
$a1° + $a2° + f°
= 180°
${$a1+$a2}° + f°
= 180°
f° = $f°
$a2° has a vertical angle in the quadrilateral. This
angle must be the same measure.
Three of the four angles of the quadrilateral are now know.
$a2° + $a3° + $a4°
+ g° = 180°
${$a2 + $a3 + $a4}° + g° = 180°
g° = $g°
@
qu.12.2.editing=useHTML@
qu.12.2.algorithm=$a1=range(40,70,1);
$a2=range(40,70,1);
$f=180-$a1-$a2;
$a3=range(100,160,1);
$a4=range(45,70,1);
$g=360-$a2-$a3-$a4;@
qu.12.2.weighting=1,1@
qu.12.2.numbering=alpha@
qu.12.2.part.1.name=$f@
qu.12.2.part.1.answer.units=@
qu.12.2.part.1.numStyle=thousands scientific arithmetic@
qu.12.2.part.1.editing=useHTML@
qu.12.2.part.1.showUnits=false@
qu.12.2.part.1.question=(Unset)@
qu.12.2.part.1.mode=Numeric@
qu.12.2.part.1.grading=exact_value@
qu.12.2.part.1.negStyle=minus@
qu.12.2.part.1.answer.num=$f@
qu.12.2.part.2.name=$g@
qu.12.2.part.2.answer.units=@
qu.12.2.part.2.numStyle=thousands scientific arithmetic@
qu.12.2.part.2.editing=useHTML@
qu.12.2.part.2.showUnits=false@
qu.12.2.part.2.question=(Unset)@
qu.12.2.part.2.mode=Numeric@
qu.12.2.part.2.grading=exact_value@
qu.12.2.part.2.negStyle=minus@
qu.12.2.part.2.answer.num=$g@
qu.12.2.question=
Find the measure of angles f ° and g °.
Do
not enter the ° into the answer box.
f° = <1>
g° = <2>
@
qu.12.3.mode=Inline@
qu.12.3.name=Multiple angles in Quad@
qu.12.3.comment=
Find the value of $x and the measures of angles labeled A and B.
Do not enter the ° symbol into the answer box.
The sum of the interior angles of a quadrilateral is 360°.
${$a4}° + ${$a1}° + (${$a}$x - $b)° + (${$c}$x - $d)° = 360°
${$a+$c}$x° + ${$a4+$a1-$b-$d}° = 360°
${$a+$c}$x° = ${360-($a4+$a1-$b-$d)}°
${$x} = ${$ansx}
Angle A = (${$a}$x - $b)° = (${$a} • $ansx - $b)° = ${$ansa}°
Angle B = (${$c}$x - $d)° = (${$c} • $ansx - $d)° = ${$ansb}°
@
qu.12.3.algorithm=$a1=range(85,110,1);
$a2=range(70,90,2);
$a3=range(95,120,2);
$a4=360-$a1-$a2-$a3;
$i=rint(4);
$x=switch($i,"w","x","y","z");
$a=range(2,5,1);
$ansx=int($a2/$a)+1;
$b=$a*$ansx-$a2;
$c=int($a3/$ansx)+1;
$d=$c*$ansx-$a3;
$ansa=$a*$ansx-$b;
$ansb=$c*$ansx-$d;@
qu.12.3.weighting=1,1,1@
qu.12.3.numbering=alpha@
qu.12.3.part.1.name=$ansx@
qu.12.3.part.1.answer.units=@
qu.12.3.part.1.numStyle=thousands scientific arithmetic@
qu.12.3.part.1.editing=useHTML@
qu.12.3.part.1.showUnits=false@
qu.12.3.part.1.question=(Unset)@
qu.12.3.part.1.mode=Numeric@
qu.12.3.part.1.grading=exact_value@
qu.12.3.part.1.negStyle=minus@
qu.12.3.part.1.answer.num=$ansx@
qu.12.3.part.2.name=$ansa@
qu.12.3.part.2.answer.units=@
qu.12.3.part.2.numStyle=thousands scientific arithmetic@
qu.12.3.part.2.editing=useHTML@
qu.12.3.part.2.showUnits=false@
qu.12.3.part.2.question=(Unset)@
qu.12.3.part.2.mode=Numeric@
qu.12.3.part.2.grading=exact_value@
qu.12.3.part.2.negStyle=minus@
qu.12.3.part.2.answer.num=$ansa@
qu.12.3.part.3.name=$ansb@
qu.12.3.part.3.answer.units=@
qu.12.3.part.3.numStyle=thousands scientific arithmetic@
qu.12.3.part.3.editing=useHTML@
qu.12.3.part.3.showUnits=false@
qu.12.3.part.3.question=(Unset)@
qu.12.3.part.3.mode=Numeric@
qu.12.3.part.3.grading=exact_value@
qu.12.3.part.3.negStyle=minus@
qu.12.3.part.3.answer.num=$ansb@
qu.12.3.question=
Find the value of $x and the measures of angles labeled
A and B.
Do not enter the ° symbol into the answer box.
$x = <1>
A = <2>
B = <3>
@
